Theorem 1 in Suppes's Axiomatic Set Theory - why is the empty set used?

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A question was recently asked about Theorem 1 of Suppes's axiomatic set theory asking why the empty set was used. I have a related question. Why, in the formula:

$(\exists{C})(\forall{x})(x \in C \iff x \in \emptyset \& (x \ne x))$

does Suppes use the empty set as the set of which $A$ is a subset? That is, wouldn't the theorem be equally valid if he had made this first line:

$(\exists{C})(\forall{x})(x \in C \iff x \in B \& (x \ne x))$

In other words, isn't the superset irrelevant (it can be $B$, $\emptyset$ or any other set) if ultimately what we are proving is that no $x$ can be a member of $A$ because x≠x is absurd?

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At this stage in the development of the theory, no sets have been defined except the empty set, (whose existence is posited as a primitive constant of the theory). It is the only primitive formula involving set that can be used in the axiom schema of separation.