How can I proof that there exists no algorithm which has a runtime of $O(n^2)$ and $\theta(n^{\frac{7}{2}})$?
Or is this possible because logically I would say that if a function is $O(n^{\frac{7}{2}})$ then it is also $O(n^2)$.
How can I proof that there exists no algorithm which has a runtime of $O(n^2)$ and $\theta(n^{\frac{7}{2}})$?
Or is this possible because logically I would say that if a function is $O(n^{\frac{7}{2}})$ then it is also $O(n^2)$.
HINT: $n^{3.5}>n^{2}$ for $n>1$