Transforming the PDE $c^2 \frac{{\partial}^2y}{\partial x^2} = \frac{{\partial}^2y}{\partial t^2}$

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If we have the PDE $ c^2 \frac{{\partial}^2y}{\partial x^2} = \frac{{\partial}^2y}{\partial t^2}$

Make the transformation $ y= z + a(x/L)sin(\omega t) $ to the above PDE to formulate a new PDE.

How would we do this?

So far I have found that $\frac{{\partial}^2y}{\partial x^2} = \frac{{\partial}^2z}{\partial x^2}$.

But I am confused as to how to find $\frac{{\partial}^2z}{\partial t^2}$.