You can fool some of the people all of the time, and you can fool all of the people some of the time, but you can't fool all of the people all of the time.
My attempt is
$$((\exists(x),A(x)) \land(\forall(x),S(x))) \land \neg (\forall(x), A(x))$$
Such that
$A(x)=$ You can fool all the time
$S(x)=$ You can fool some of the time
Just starting out basic logic and I'm looking to see where I"m making mistakes. Thanks
Your attempt isn't entirely satisfactory because you ignore the fact that the sentence quantifies over times. Here's a better translation, I think:
$\exists x \forall y Fxy \ \wedge \exists y \forall x Fxy \ \wedge \neg \forall x \forall y Fxy$.
The interpretation of $Fxy$ is "x is fooled at time y".