Transpose of rational matrix is also rational

87 Views Asked by At

Rational numbers can be defined as those numbers $a \in \mathbb{R}$ for which there exists an integer $v \in \mathbb{Z}$ such that $av \in \mathbb{Z}$. Let us consider the following higher-dimensional extension of this definition.

Definition: A matrix $A \in \mathbb{R}^{n \times n}$ is rational if there exists a vector $v \in \mathbb{Z}^n \setminus \{0\}$ such that $Av \in \mathbb{Z}^n$.

I would like to show the following.

Conjecture: If $A$ is rational, then $A^T$ is also rational.

My most promising proof attempt has been to note that singular matrices are rational according to the above definition and singular matrices are closed under transposition. So maybe it is possible to adapt that proof to the situation here?

1

There are 1 best solutions below

1
On BEST ANSWER

How about $$A=\pmatrix{\sqrt2&\sqrt2\\\sqrt3&\sqrt3}?$$