ABCD is a parallelogram.
E is the point where the diagonals AC and BD meet.
Prove that triangle ABE is congruent to triangle CDE.
2026-04-02 05:18:00.1775107080
Triangles within a Parallelogram
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AE and EC are on the same line, so have the same gradients. Same goes for BE and ED. Because it is a parallelogram, AB=CD, as it has to be so that the shape holds. Therefore, you have proved this by the Angle-Side-Angle rule, where two triangles with two identical angles and a side are congruent, even if they are reflected.
If you know the gradient, and set the known side to 0 degrees, the gradient shows the vector, which is also an angle.