Triangulable linear transformation restricted to an invariant vector space is triangulable

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Suppose $V$ is a vector space of finite dimension and $f:V \rightarrow V$ is a linear transformation which is triangulable. If $W$ is an $f$-invariant subspace of $V$, show that $f \mid _W$ is also triangulable.

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If a matrix is triangulabe, what you can say about it's characteristic polynomial? Then what is the relationship between characteristic polynomial of $f$ and the characteristic polynomial of $f_{\mid W}$?