Trigonometric Substitution (Basic)

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Can someone help me find the integrals for the ff:

$$\int \frac{\sqrt{9z^{2}-1}}{27z^{4}}\,dz$$

$$\int y^{2}\sqrt{25-y^{2}} dy$$

For the second one I have tried to do answer it and this is what I have made:

$x=5\sin(\theta) $

$dx=5\cos(\theta)\,d\theta$

$\int 25\sin^{2}\theta \sqrt{25-25\sin^{2}\theta }\cdot 5\cos\theta\, d\theta$

$625\int \sin^{2}\theta \cos^{2}\theta\, d\theta $

$625\int (1-\cos^{2}\theta ) \sin^{2}\theta \cos^{2}\theta\, d\theta $

and at this point i'm not sure if I did it correct or not.

and

$$\int \frac{dx}{x^{2}{\sqrt{4x^{2}-9}}}$$

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Hints:

  1. Take $z=\frac13\sec\theta$

  2. Take $y=5\sin\theta$

  3. Take $x=\frac32\sec\theta$