So I'm doing a physics problem on conversions, and having a bit of trouble with the intermediate steps (since I keep getting the wrong answers. The problem is as follows:
Suppose that it takes 18.2 hours to drain a container of 76.0 $m^3$ of water. What is the “mass flow rate,” in kg/s, of water from the container? (Assuming that each cubic centimeter of water has a mass of exactly 1g)
My process went something like this (after dividing 76 by 18.2):
$$\frac{4.17582m^3}{1hr} \cdot (\frac{1cm}{0.01m})^{3} \cdot \frac{1g}{1cm^3} \cdot \frac{1kg}{1000g} \cdot \frac{1hr}{60min} \cdot \frac{1min}{60sec}$$
which got me the answer: 1.16 kg/sec (rounded to 3 significant figures). Is this the right process?