$\frac{1}{4} (\frac{1}{4} \sec^2(\frac{1}{4}) + 2\tan(\frac{1}{4})) $
How do I input $\sec^2 $ onto the calculator ?
$$\sec(x)=\frac{1}{\cos(x)}$$ and $$\sec(x)^2=\frac{1}{\cos(x)^2}$$ and in your case $$\left(\sec(1/4)\right)^2=\frac{1}{(\cos(1/4))^2}$$
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$$\sec(x)=\frac{1}{\cos(x)}$$ and $$\sec(x)^2=\frac{1}{\cos(x)^2}$$ and in your case $$\left(\sec(1/4)\right)^2=\frac{1}{(\cos(1/4))^2}$$