True or false: every non-zero vector is parallel to a unit vector

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The correct answer is True but I don't understand how this is.

How about a vector of value 2? This is a non-zero vector. How can this be parallel to a unit vector?

The explanation I'm given:

"Remember that two vectors $\vec a$ and $\vec b$ are parallel if $$\vec a = \lambda \vec b$$ for some scalar $\lambda$.

Also remember that $|\lambda \vec a| = |\lambda||\vec a| $.

So given a vector $\vec a$, what value of $\lambda$ will give a vector $\vec b = \lambda \vec a$ which has magnitude $1$?

The correct answer is 'True'."

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Let $\mathbf{u}$ be a non-unit vector. Set $\mathbf{n} = \mathbf{u}/|\mathbf{u}|$. Then $\mathbf{n}$ is a unit vector and $\mathbf{u}$ is parallel to $\mathbf{n}$ since $\mathbf{u} = |\mathbf{u}| \, \mathbf{n}.$

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A vector doesn't have "a value 2". It has a length and a direction. Vectors are parallel if they have the same direction. The length doesn't matter. A vector is a unit vector if its length is 1. The direction doesn't matter.

So to find a unit vector parallel to some other vector, you need it to point in the same direction, and to have length 1.