$u_{t}+cu_x=f(x+ct)$ $\implies$ $\frac{du}{dt}=f(x+ct)$

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I'm working on a PDE problem and I came across a step I just can't figure out, would appreciate any help.

The question involves solving the general wave equation. I've got to here $$u_{t}+cu_x=f(x+ct)$$ The problem I'm having is what comes after.

(1) How do we derive $\frac{dx}{dt}=c$?

My best guess is that for any $au_x+bu_y=g$, we can deduce that $\frac{dy}{dx} = \frac{b}{a}$. How though?

(2) The solution defines paths $\frac{dx}{dt}=c$ and $x(h,0)=h$. What is the point of the latter?

(3) After defining the path, the biggest problem I have is how they jump to $$\frac{du}{dt}=f(x+ct)$$

Would appreciate any help understanding any of these. Thank you