Ultrafilter Lemma and Dimension Theorem

162 Views Asked by At

Reading on Wikipedia I find out that (the uniqueness in) the Dimension Theorem for arbitrary Vector Spaces can be proved using just the Ultrafilter Lemma (a strictly weaker version of Axiom of Choice). Is it hard to prove using just Ultrafilter lemma? Is there any references I could see?

1

There are 1 best solutions below

0
On BEST ANSWER

You can find the proof in the paper:

James D. Halpern, Bases in vector spaces and the axiom of choice, Proc. Amer. Math. Soc. 17 (1966), 670--673.