Unbounded Function Becomes Bounded through Polar Transformation?

64 Views Asked by At

$D=\{(x,y)|5x^2+6y^2\leq1\}$

$\int\int_D \frac{x^2}{(5x^2+6y^2)^\frac3 2}$

The integrand is not bounded. When performing a polar transformation for the ellipse domain the integrand becomes bounded since the Jacobean is $\frac{1}{\sqrt40}r$:

$\frac{1}{\sqrt 40} cos^2(\theta)$

I was wondering what is the reason for that and if there is an intuitive way of understanding this transformation.