Unconditional bases equivallent to permutations of basis elements.

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On page 9 of The Handbook of the Geometry of Banach Spaces: Volume I I found the following:

"A basis $\{x_n\}_{n=1}^{\infty}$ is said to be an unconditional basis provided that $\sum \alpha_n x_n$ converges unconditionally whenever it converges. This is equivalent to saying that every permutation of $\{x_n\}_{n=1}^{\infty}$ is also a basis."

How are those two statements equivalent?

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Use the following:

Let $X$ be a Banach spacce.

1) $(y_n)$ is a basis of $X$ if and only if each $x\in X$ has a unique representation $\sum\limits_{i=1}^\infty \alpha_i y_i$.

2) If $\sum\limits_{i=1}^\infty z_i$ converges unconditionally to $z$, then any rearangement of $\sum\limits_{i=1}^\infty z_i$ converges to $z$.

3) If $(x_n)$ is a basis of $X$ with coefficient functionals $(x_n^*)$ and if $x=\sum\limits_{i=1}^\infty \alpha_i x_{\pi(i)}$, then $x_{\pi(i)}^* x= \alpha_i$.