I have a statement like this: if 4x - 3 is even then x is odd. What does providing the predicate for the starting assumption and the predicate for the concluding assumption for a proof by contraposition mean?
Current I have some like this as the predicate for the starting assumption:
P(x) = 4x - 3 is odd
Is this sufficient? or do I need to go further.
Given that you have to prove $P \implies Q$ for two propositions $P$ and $Q$, the contraposition asks you to prove the equivalent statement $\neg Q \implies \neg P$, where $\neg$ stands for negation.
Therefore, for attempting a proof by contraposition, the starting assumption is $\neg Q$, where $Q$ is the conclusion of the original statement.
Similarly, the conclusion of a proof by contraposition, is $\neg P$, where $P$ is the starting assumption of the original statement.
In our case, we have $P = 4x-3$ is even and $Q = x$ is odd.
Hence, $\neg Q = \mathit{x}$ is even and $\neg P = \mathit{4x-3}$ is odd are the starting assumption and conclusion of a proof by contraposition, respectively.
Therefore, for attempting a proof by contraposition, you start with the fact that $x$ is even. You should now show that $4x-3$ is odd, which is the conclusion,using the starting assumption.
Note : In our case, it turns out the conclusion is true if $x$ is any integer, so starting assumption is somewhat stronger than required.