I need to find for which $a,b$ The following integral converges.
$$ \int^{\pi/2}_{0}\frac{(\pi/2 - x)^ax^b}{\cos(x^2)^b}dx $$
Now, my problem is that the answers say that the point $x=0$ Is problematic. I don’t understand why, the function is defined and bounded at $x=0$, what is the problem at that point?
Help please.
Thanks.