Uniform continuous and bounded set of functions is closed under scalar multiplication

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$f(x)\in C_{ucb}$ (Uniformly continuous and bounded functions)

Show $cf(x)\in C_{ucb}$

Would it be enough to write:

$\forall \epsilon>0$; $ \exists \delta>0$ such that $|x-y|<\delta \rightarrow|cf(x)-cf(y)|<\epsilon^*$

$|f(x)-f(y)|<\frac{\epsilon^*}{|c|}$; where $c\neq0$ and $\frac{\epsilon^*}{|c|}=\epsilon$

I'm not using my bounded condition.