Uniform convergence on sequence of contractions composition

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Let a sequence $f_k$ where $f_k:\mathbb {R^n} \rightarrow \mathbb{R^n}$ and each $f_k$ is a contraction.

Defining $F_k=f_0 \circ ... \circ f_k$ i want to show that $F_k \rightarrow C$ where $C$ is Constant and the convergence is uniform

Proving that $F_k$ converges to a Constant is easy, but i don't know How to show this convergence is uniform

Edit: I have seen my mistake and accepted the answer, indeed we need the assumption of bounded derivative on each function of sequence otherwise one can play with coefficients

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For each nonnegative integer $u$, let $$a_u=1-\frac{1}{(u+2)^2}$$ and let $f_u:\mathbb{R}^n\to\mathbb{R}^n$ be defined by $$f_u(x)=a_u x$$ It's easily seen that each $f_u$ is a contraction.

But for each $x\in\mathbb{R}^n$, we have \begin{align*} \lim_{k\to\infty}F_k(x) &=\lim_{k\to\infty}(f_0\circ\cdots\circ f_k)(x)\\[4pt] &=\left(\lim_{k\to\infty}\left(\prod_{u=0}^k a_u\right)\right)\!x\\[4pt] &=\left(\prod_{u=0}^\infty a_u\right)\!x\\[4pt] &=\left(\prod_{u=0}^\infty \left(1-\frac{1}{(u+2)^2}\right)\right)\!x\\[4pt] &=\left({\small{\frac{1}{2}}}\right)\!x\\[4pt] \end{align*} so $F_k$ does not approach a constant.