Uniform distribution

Question

$X~U(0,1)$ Find $E[\sqrt {X}]$ and the probability density function of $Y$ defined as $Y=X^2$.

I know that $E[Y]=E[g(X)] = \int_a^b g(x)f(x) dx$ I don't know why this question does not meet the quality standards.

Answer 1

$\mathbb{E}(\sqrt{X})=\int_{-\infty}^\infty \sqrt{x} f(x) dx = \int_0^1 \sqrt{x} dx = \frac{2}{3} x^{\frac{3}{2}}|_0^1=\frac{2}{3}$ If $Y=X^2$ then $F_Y(y)=\mathbb{P}\{Y\leq y\}=\mathbb{P}\{X^2\leq y\}=\mathbb{P}\{X\leq \sqrt{y}\}=F_X(\sqrt{y})=\sqrt{y}$. Therefore $f_y(y)=\frac{\delta}{\delta y}F_y(y)=\frac{1}{2}y^{\frac{-1}{2}}$.