Unique solution for PDE?

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How can one tell if a solution is existent or unique? For example:

$yu_y+uu_x=u-y$

$u(x,1)=x$

I've found the solution to be $u=x+1-y$, but have been told there are infinitely many solutions.

Is there a condition that must be satisfied for a unique solution?

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Follow the method in http://en.wikipedia.org/wiki/Method_of_characteristics#Example:

$\dfrac{dy}{dt}=y$ , letting $y(0)=1$ , we have $y=e^t$

$\dfrac{du}{dt}=u-y=u-e^t$ , letting $u(0)=u_0$ , we have $u=(u_0-t)e^t=(u_0-\ln y)y$

$\dfrac{dx}{dt}=u=(u_0-t)e^t$ , we have $x=(u_0+1-t)e^t+f(u_0)=u+y+f\left(\dfrac{u}{y}+\ln y\right)$ , i.e. $\dfrac{u}{y}+\ln y=F(x-y-u)$

Consider the general solution $x=u+y+f\left(\dfrac{u}{y}+\ln y\right)$ :

$u(x,1)=x$ :

$f(x)=-1$

$\therefore x=u+y-1$ , i.e. $u=x-y+1$

But consider the general solution $\dfrac{u}{y}+\ln y=F(x-y-u)$ :

$u(x,1)=x$ :

$F(-1)=x$ , which is impossible.

$\therefore$ There is no solution.

Hence the PDE has the unique solution $u=x-y+1$ .