$f(x) = 2^x - \sin x, [0,π]$
I believe the question wants me to find the values x within the interval that have the same slope as the secant line?
The secant line would be:
$$ f'(c) = \frac{f(π) - f(0)}{π - 0}$$ which is
$$ f'(c) = \frac{2^π - 1}{π}$$
The derivative of f(x) is:
$$f'(x) = 2^x\ln2 - \cos x$$
In my calculator (TI-84 Plus) I am plotting the graph of f'(x) and then pressing calculate for the value of f'(c). Depending on my input I either get the wrong answer or I get a syntax error. What is the correct method of doing this on a graphing calculator?