Using change of basis to construct system of equations

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I've been studying linear algebra and have gotten the general understanding that when we are looking at a vector described by two separate bases, that we can generally apply:

$[u]_{T} = P_{S \rightarrow T}[u]_S$

Now, I am trying to apply this to this problem:

The problem I am trying to solve now:

Now, to address this problem I modeled $P_{s \rightarrow T}$ as \begin{bmatrix} a & b \\ c & d \\ \end{bmatrix}

Then, I set up my equations, fulfilling the inital equation, but hopefully giving me a system of equations to solve for $a, b, c, d$:

$\begin{bmatrix} a & b \\ c & d \\\end{bmatrix} *\begin{bmatrix} 11 \\ 5 \\\end{bmatrix} = \begin{bmatrix} 4 \\ 3 \\\end{bmatrix}$

$\begin{bmatrix} a & b \\ c & d \\\end{bmatrix} *\begin{bmatrix} 0 \\ -7 \\\end{bmatrix} = \begin{bmatrix} 1 \\ -2 \\\end{bmatrix}$

The answer is shown to be

enter image description here

However, from my system I can see that these are not the values that I would obtain, as from performing a bit of mental matrix multiplication, I can see that $b = -\frac{1}{7}$, and this is obviously wrong. This leads me to believe there is something wrong with my method.

I understand this is very simple math for many people in this community, but would really appreciate someone taking the time to point me in the right direction

Thank You,

David

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You need to write your equations the other way around: $$\begin{bmatrix} a & b \\ c & d \\\end{bmatrix} \begin{bmatrix} 4 \\ 3 \\\end{bmatrix} = \begin{bmatrix} 11 \\ 5 \\\end{bmatrix} $$ and $$ \begin{bmatrix} a & b \\ c & d \\\end{bmatrix} \begin{bmatrix} 1 \\ -2 \\\end{bmatrix}=\begin{bmatrix} 0 \\ -7 \\\end{bmatrix} . $$


For matrices:

When you express a linear operator as a matrix, there are two bases involved: one for the domain and one for the codomain. So if you are changing both bases, the change of basis is $$[u]_T=P^{-1}[u]_SP.$$