Given $z_1,z_2,z_3,z_4$ 4 different points of $ {\mathbb C}$, we define the cross ratio $(z_1,z_2,z_3,z_4)$ as
$(z_1,z_2,z_3,z_4)\longrightarrow [z_1,z_2,z_3,z_4]$
As a first step, we had to show that there is an invariance of cross ratio under Möbius transformation , what I did.
I'm stuck here , how can I prove :
$$[z_1,z_2,z_3,z_4]=\frac{(\frac{z_1-z_3}{z_2-z_3})}{(\frac{z_1-z_4}{z_2-z_4})}$$
And I found this following statement
$ABC$ a triangle in complex plane & $\;P,Q,R\;$ 3 points such that :
$P \in (BC) \; , \;Q \in (CA)\;,\; R \in (AB) $
$(QR)\; $and $(BC)$ are concurrent at a point D
We have :
$$\frac{\overline{PC}}{\overline{PB}} \, .\frac{\overline{QA}}{\overline{QC}} \, . \frac{\overline{RB}}{\overline{RA}}=[C,B,A',D]$$
How can I prove it ?
Thanks in advance for your help.
I'm not sure if this serves as an answer, but I wanted to post these images, which I pulled straight out of my homework.