The prompt is to evaluate the integral $\iint_D|x-y|\,dx\,dy$ where $D= \{(x, y) \in R^2 : x \ge 0, 0 \le y \le 3-2x \}$
Plotting the graph for the region looks something like this
Looking at the graph we can tell, $$\int_0^{3}\int_{0}^{3-2x}|x-y|\,dx\,dy$$
Is this the correct way to evaluate limits? What are we supposed to do with the modulus?
Hint: As you have a mod inside the integral, you need to get rid of it. On the drawing that you have made, also draw the line $x-y=0$. This will divide your region into two halves; without the mod. Calculate area of both the regions and then add them. Try it, if you still have trouble, comment below.