Say I have the following two equations:
$$2000 = k \ln {\frac{t+1}{t}}$$ $$2000 = k \ln {\frac{t+3}{t+1}}$$
The solution for $t$ is $t=1$, which is easily obtained equating the two equations and exponentiating both sides.
In Maple, this is:
e1 := 2000 = k*ln((t + 1)/t)
e2 := 2000 = k*ln((t + 3)/(t + 1))
solve({ e1, e2 }, { t })
The $solve$ command produces no result above. If instead I do
e3 := k*ln((t + 1)/t) = k*ln((t + 3)/(t + 1))
solve(e3, t)
I obtain the correct answer $t=1$.
Why doesn't the solve command work when $e1$ and $e2$ are considered a system of two equations?
works fine, and returns the solution. You asked for maple to solve the system for
tbut to keepkarbitrary -- there is indeed no solution then.