Using Van-Kampen in $S^1\times S^1$ as cylinder

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I was trying to use Van-Kampen theorem to compute $S^1 \times S^1$ using its representation as a cylinder.

$U$= from a little below the middle circle to the upper part of the cylinder.

$V$= from a little above the middle circle to the bottom part of the cylinder.

Then $U$ is homotopic to the upper $S^1$. Similarly, $V$ is homotopic to the bottom $S^1$ The intersection of $U$ and $V$ is homotopic to the middle circle, $U \cap V = S^1$.

Then $\pi(U)=<\alpha>$, $\pi(V)=<\beta>$, $\pi(U\cap V)=<\gamma>$. Now $\alpha$ and $\beta$ are homotopic since the upper circle and the bottom circle are relative.

$\pi(X)=<\alpha,\beta \mid \alpha=\beta>=<\alpha>$.

I know this is wrong but I don't understand where. I know that using the rectangular representation of the torus we can use Van-Kampen, just taking a point out and then a circle and we will get $\pi(X)=<\alpha,\beta \mid \alpha*\beta*\alpha^{-1}*\beta^{-1}=1>$.

I am trying to use van Kampen in this example and I cant do it. Even more general, Can we use van Kampen in $X\times Y$.

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The product $S^1\times S^1$ is not a cylinder. It's a torus.

So what you've done is a correct computation of the fundamental group, but of a wrong space.

In general if you want to compute the fundamental group of a product of spaces, you don't need van Kampen. The group $\pi_1(A\times B)$ is just going to be the product of the fundamental groups $\pi_1(A)\times\pi_1(B)$. It's easy to see, since any loop in $A\times B$ is just a product of loops in $A$ and in $B$.