Variance equivalences

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I am working through Foundation Maths seventh edition. I got stuck while trying to proof the following statement:

$∑(x - x̄)^2 = ∑(x^2) - n·x̄^2$

Is someone able to show what steps are needed to go from the absolute difference to $∑(x^2) - n·x̄^2$

Thank you!

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$$\sum(x-\mu)^2=\sum x^2+\sum\mu^2-\sum2\mu x=\sum x^2+n\mu^2-2\mu\sum x$$

Recall now that:

$$\mu=\frac{1}{n}\sum x,\quad n\mu=\sum x$$

Which implies the variance is:

$$\sum x^2+n\mu^2-2\mu(n\mu)=\sum x^2-n\mu^2$$