Variance of Random Exponential Variables

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Just a note: this is a homework question, so feel free to prod me towards the answer if you want :) Also, I'm pretty bad at statistics so sorry in advance if I'm stupid :/

For some $ X_1 ... X_n \sim Exp(\lambda) $ i.i.d. random variables, I have an estimator:

$ \hat{\lambda} = (\frac{1}{n} \sum_{i = 1}^{n}{X_i})^{-1} $

I need to use the CLT to determine an approximate $ 1 - \alpha $ stochastic confidence interval for $ \frac{1}{\lambda} $ based on $ \hat{\lambda} $.

Obviously, I need to find the mean $ \mu $ and variance $ \sigma^2 $ so that I can normalise it (i.e. $ \frac{\hat{\lambda} - \mu}{\sigma} \sim Normal(0, 1) $).

The thing I'm not sure on is how to find $ \mu $ and $ \sigma^2 $.

I'm mostly comfortable saying that since $ \frac{1}{n} \sum_{i = 1}^{n}{X_i} $ is the sample mean, $ E[\hat{\lambda}] = \lambda $

With the variance though, I'm really not sure. My best guess is that it's:

$$ Var(\hat{\lambda}) = (Var(\frac{1}{n} \sum_{i = 1}^{n}{X_i}))^{-1} $$

$$ Var(\hat{\lambda}) = (\frac{1}{n^2} \dot{} Var(\sum_{i = 1}^{n}{X_i}))^{-1} $$

$$ Var(\hat{\lambda}) = (\frac{1}{n^2} \dot{} n \dot{} \frac{1}{\lambda^2} )^{-1} $$

$$ Var(\hat{\lambda}) = n\lambda^2 $$

But I'm not sure if you're do that with variances. Any help would be appreciated :)