Is there an intuitive way to see that the vector field $$\begin{equation} v=\begin{cases} \dot z=e^{\frac{1}{z}}\\ \dot w=e^{\frac{1}{w}} \end{cases} \end{equation}$$ is tangent to a singular holomorphic foliation on $\mathbb{C}^2$ with singular set $\Sigma=\{zw = 0\}$?
2026-03-25 17:38:39.1774460319
Vector field tangent to a singular holomorphic foliation
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