Vectors a, b and c are present.
Given $a+b+c=0$, show that $a\times b=b \times c= c\times a$
I have tried starting from $a+b=-c$ and $a+c=-b$
then $-b \times -c=(a+c)(a+b)$
But somehow its not making sense.
How does one prove it?
Vectors a, b and c are present.
Given $a+b+c=0$, show that $a\times b=b \times c= c\times a$
I have tried starting from $a+b=-c$ and $a+c=-b$
then $-b \times -c=(a+c)(a+b)$
But somehow its not making sense.
How does one prove it?
From $a\times (- a) =0$ and $-a=b+c$, one can get $$a\times (b+c)=0,$$ i.e., $a\times b=-a\times c=c\times a$. The other equality can be proved similarly.