If a and b are two unit vectors, then the sum of the integers in the range of $\frac{5}{2}|a+b|+6|a-b|$ is
(1) 0
(2) 25
(3) 64
(4) 81
If a and b are two unit vectors, then the sum of the integers in the range of $\frac{5}{2}|a+b|+6|a-b|$ is
(1) 0
(2) 25
(3) 64
(4) 81
Disclaimer: This is an answer suitable for multiple choice questions only.
Let, $$f(a,b)=\frac{5}{2}|a+b|+6|a-b|$$
For $b=a$, $f(a,b)=5$, for $b=-a$, $f(a,b)=12$. So the range of $f$ is atleast $[5,12]$. Sum of integrs from 5 to 12 is $$\frac{12*13}{2}-\frac{4*5}{2}=68$$
Therefore the only remaining choice is 81.