I thoght Proof of Corollary 3.3 (ii) is not complete.
As E is not shown to be measurable there.
I thought following argument . As the complement of a measurable set is measurable then $E_1^c, E_2^c....$ are measurable.
this sequence is increasing like (i)
Using that $m(E^c)=\lim_{N\to\infty}m(E_N^c)$
and $E^c=\cup E^c_N$ so it is measurable.
Complement is also measurable
SO E is measurable.
Please See my argument. If there is any other argument please suggest.


$E$ is shown to be a measurable set here; from the marked identity:
$$E = E_1 \setminus \bigcup_{k=1}^\infty G_i$$
$E_1$ is measurable and so are the $G_i$ as differences of measurable sets so $E$ is measurable. I don't see any incompleteness. The author could have made it more explicit perhaps. But from the start $E=\bigcap E_n$ is clearly measurable when all $E_n$ are. (That's what $E_n \searrow E$ means.)