New to this, would this be correct?
If we have $A = {1,2,3}, B = Z^{+}, C = [1,\infty)$
Where $C = {x \in R : x \geq} 1 $
Then $B-A $ would be:
$(x \in Z^{+}, x>3) $
and $C-A$ would be:
$(x \in R, x>3)$
New to this, would this be correct?
If we have $A = {1,2,3}, B = Z^{+}, C = [1,\infty)$
Where $C = {x \in R : x \geq} 1 $
Then $B-A $ would be:
$(x \in Z^{+}, x>3) $
and $C-A$ would be:
$(x \in R, x>3)$
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$C-A$ should include some elements that are less than $3$ as well. For example $1.5$ is in $C-A$. It has not been excluded.
$$C-A=(1, \infty) \setminus \{2,3\}=(1,2) \cup (2,3) \cup (3, \infty).$$