Very simple question : normed space is subspace of its bidual

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Let $X$ be a normed space and $X^{**}$is its bidual.

I’m trying to show $X \subseteq X^{**}$.

Let $J:X \to X^{**} $ be canonical embedding. Since it is an isometry (I’ve shown that) it is invertible.

$x \in X$ then $J(x) \in X^{**}$ thus $J^{-1}(J(x))=x$. How can I say $J^{-1}(J(x)) \in X^{**}$?

I think I’m writing unnecessary things. I couldn’t show $x \in X^{**}$. It is probably so easy but I’m stuck.

I’m sorry in advance if there is any mistake.

Thanks for any help.

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$X \subseteq X^{\ast\ast}$ is misleading: It's rather $J[X] \subseteq X^{\ast\ast}$, which is isometrically isomorphic to $X$, via $J$, so $\|J(x)\|=\|x\|$ (in the respective norms on $X^{\ast\ast}$ and $X$).

So we can conceptually see $J(x)$ (i.e. all point evaluations) as a "copy" of $X$ inside $X^{\ast\ast}$.

So no need to mess with $J^{-1}(J(x))$, that's just $x$ by definition.