I found a seemingly elegant, visual argument that shows why the four colour theorem (4CT) is true. The argument is as follows (I drew some pictures as well so I hope that helps):
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Once again, I have a strong feeling that this proof is incorrect given that I cannot find a peer-reviewed mathematics paper that details its derivation.
Question: Is it a fake proof?
Source of Proof: https://www.youtube.com/watch?v=X8nA7x6Db1I The proof is from 2:15 - 3:45

You can triangulate a planar graph by adding edges to it. If the resulting triangulated graph is 4-colourable, then that same colouring will also be a valid 4-colouring of the original graph. Adding edges only imposes more restrictions, making colouring it harder. So if you can prove that all triangular planar graphs are 4-colourable, then all planar graphs are. But nowhere in that quoted text is there anything resembling a proof that all triangular planar graphs are 4-colourable - it just shows a few triangular planar graph examples and no more. That is not a proof.
Looking at the video, it is not much better. At a certain point it claims without proof that you only need a fourth colour for the border area. At that point it seems to confuse the colouring of the regions of a map and the colourings of its dual graph.
It is fairly easy to construct a graph (or its dual map) that needs 4 colours and for which all four colours must occur on some of the internal vertices (or regions on the dual map).
Here is one such graph:

If you colour it starting from the three corners (which must have distinct colours because they connect as a triangle), it becomes clear that there is only one way to colour the four internal vertices and that they use all 4 colours.
So there are graphs/maps that need at least 4 colours on internal vertices/regions. The video assumes that this is not possible, and so certainly does not prove that there is no graph/map that needs a fifth colour on some vertex/region.