Volume generated by revolving region of $y=-1,y=\ln x,x=y^2+1$ about $y=1$

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I am trying to find the volume of solid generated by revolving region of $y=-1,y=\ln x,x=y^2+1$ about $y=1$ using shell method. here is the picture. enter image description here

I need help in setting up the integral? I actually figured out that $$V=2\pi\int_{-1}^{0}(1-y)(y^2+1-e^y)dy$$ But i am not sure?