Can anyone check if I am correct?
I see it as paraboloid and cone that intersect at circle.
I'm doing it using polar form to make it easier.
$4 \int_{0}^{\frac{\pi}{2}}d\theta \int_{0}^{\sqrt{2}}dr \int_{r^2}^{4-r^2}r\ dz $
Can anyone check if I am correct?
I see it as paraboloid and cone that intersect at circle.
I'm doing it using polar form to make it easier.
$4 \int_{0}^{\frac{\pi}{2}}d\theta \int_{0}^{\sqrt{2}}dr \int_{r^2}^{4-r^2}r\ dz $
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