An open rectangular tank of depth $2.4$m has a horizontal base of length $3.8$ m and breadth $2.1$m.
A solid metal cylinder of volume $0.865m^3$ rests with its curbed surface on base in the tank .
$6400$ litres of water is poured into the tank at rate of $900 cm^3/s$
Calculate how many hours and minutes it takes for all the water to be poured in , giving answer to nearest minute.
My working is -
Vol of tank = $2.4 \times 3.8 \times 2.1 = 19.152m^3$
After here I'm not too sure how to carry on
There is just a bunch of extraneous information to confuse you. The time is just the volume divided by the rate: $$6400\,L\times\frac{1000\,cm^3}{L}\times\frac{1\,s}{900\,cm^3}\approx7111.1\,s=1:58:31.1$$ or $1$ hour, $59$ minutes to nearest minute.