Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the following curves about the line y=−1.
$y=x^2$ and $x=y^2$
What I got so far was $\int_{0}^1 2\pi (y+1) (y^2-y^\frac{1}{2}) dy$, when I solve it though I get $-\frac{29\pi}{30}$. This is the wrong answer can someone tell me where I did something wrong? Because I can not tell.
What doobdood said was right all I had to do was changed $y^2-y^\frac{1}{2}$ to $y^\frac{1}{2} - y^2$, where the answer to the question would be $\frac{29\pi}{30}$ if the correct answer. Thank you Doobdood.