We can suppose without loss... General Dirichlet question

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I would like to know why I can start supposing that $\sigma_{0}=0$ in the proof of the following theorem about Dirichlet series:

"Let $a_{n}\ge0$ for every $n\ge1$. Then the point $s=\sigma_{0}$ is a singularity of $f$."

Where $f$ is the Dirichlet series $\displaystyle\sum_{n=1}^{\infty}\frac{a_{n}}{n^{s}}$ and $\sigma_{0}$ is the abscissa of convergence.

If needed for more context I can indicate the full proof of the theorem.

Thank you in advance!

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Say $f(s)=\sum\frac{a_n}{n^s}$. Define $g(s)=f(s+\sigma_0)$. Then $g(s)=\sum\frac{b_n}{n^s}$ where $b_n=a_n/n^{\sigma_0}\ge0$.