We take the equation : $(F): x^7 \equiv 2 (mod5)$
Let be $x$ the solution of $(F)$
Prove that: $$x \wedge 5=1$$
I'm lost please give me a help
2026-05-05 04:38:37.1777955917
We take the equation : $(F): x^7 \equiv 2 (mod5)$
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