The problem is from Stein and Shakarchi's Functional Analysis:
a) Let $f_{n}(x) = sin(2πnx), f_{n} ∈ L p ([0, 1])$ with $p ∈ [1, ∞)$. Show that $f_{n}$ converges to $0$ weakly in $L p$.
b) $f_{n}(x) = n^{1/p}χ(nx)$ in $Lp(R)$. Then $f_{n} → 0$ weakly if $p > 1$, but not when $p = 1$. Here$ χ$ denotes the characteristic function of $[0, 1]$.
c) $f_{n}(x) = 1 + sin(2πnx)$ in $L1([0, 1])$. Then $f_{n} → 1$ weakly also in $L1([0, 1])$, $||f_{n}||_{L1} = 1$, but $||f_{n} − 1||_{L1}$ does not converge to zero.
I know the solution for part b), I need help in a) and c), we may check them for simple functions.
Use the Riesz Representation theorem: Let $1 ≤ p < \infty.$ Suppose $\Lambda$ is a bounded linear functional on $L^p([0,1])$. Then there is a function $g \in L^q([0,1])\subseteq L^1([0,1])$, where $q$ is the conjugate of $p$, for which $\Lambda f=\int_0^1g(x)f(x)dx$ for each $f\in L^p([0,1])$. Then, $\Lambda f_n=\int_0^1g(x)\sin 2\pi nxdx$. The result now follows from the Riemann–Lebesgue lemma.
To prove that $\|f_{n} -1\|\nrightarrow 0$, note that $\int_0^1|\sin 2\pi nx|dx=2n\int_0^{1/2n}\sin 2\pi nxdx=\frac{2}{\pi}.$