If I understand a set to be recursively enumerable, if it is a projection of a recursive set, meaning it is a set of the form $\left\{ (x_1, \dots,x_{l-1}) |\exists x_l: (x_1, \dots,x_{l-1},x_l) \in A \right\}$, where $A$ is a recursive set. How can I then prove, that I could weaken this definition to: $A \subseteq \mathbb{N}^l$ is recursively enumerable if and only if it is the projection of primitive recursive set ?
2026-04-03 22:37:25.1775255845
Weaker definition of recursively enumerable sets
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The details depend on how you approach the subject. But for example if we do it through Turing machines, we can use the fact that the following predicate, traditionally called the $T$-predicate, is primitive recursive. Here $$T(e,z,x_1,x_2,\dots, x_n)$$ holds if $e$ is the index of a Turing machine, and $z$ is the index of a computation, with final result $0$, (for *true," people in logic sometimes make strange choices), when machine $e$ is given input $(x_1,x_2,\dots,x_n)$.
The point is that you can tell primitive recursively whether a number encodes a sequence of states/tape contents/head positions that is a terminating computation using machine $e$ and given input.
Things do not change very much if you approach the question through $\mu$-recursion.