I have to prove that $$\wedge^{2} \ (\mathbb{Q}/ \mathbb{Z}) = 0$$ where $\wedge$ is the wedge product.
Any hint ?
2026-03-25 18:52:36.1774464756
$\wedge^{2} \ (\mathbb{Q}/ \mathbb{Z}) = 0$
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In $\mathbb{Q} / \mathbb{Z}$, every element has finite order. On the other hand, you can also divide by any integer in $\mathbb{Q} / \mathbb{Z}$. Use bilinearity.