How to find a birational transformation that turns the equation $3(y^2-1)=2x^2(x^2-1)$ into Weierstrass form? Thanks!
2026-04-06 15:07:56.1775488076
Weierstrass form for some equation
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1
First you can expand all terms and divide by $3$ to get
$$ y^2 = \frac{2}{3}x^4-\frac{2}{3}+1 $$
Then you can readily apply Theorem 6 from
http://homepage.uconn.edu/alozano/info/constrECrank_ALM.pdf
to get
$$ v^2 = u^3 - \frac{2}{3}u^2 - \frac{8}{3}u + \frac{16}{9} $$
with
$$ u = \frac{2(x-\frac{2}{3})}{y}, v = -1+\frac{u^2x}{2} $$
According to Sage the elliptic curve has rank $2$ and $2$ torsion points.