X : 2 = 7
Y : 2 = 6
X + Y = 15
Find X and Y.
I think maybe this is some unpositional number system. I've tried positional, and it works for basis 21 (if we take X=D, and Y=C), but professor told me that even if that works, it's not solution.
X : 2 = 7
Y : 2 = 6
X + Y = 15
Find X and Y.
I think maybe this is some unpositional number system. I've tried positional, and it works for basis 21 (if we take X=D, and Y=C), but professor told me that even if that works, it's not solution.
Well, $2$ weird solutions related to "geometrical solution":
Solution 1: suppose we have a circle, and $X,Y$ are certain arcs.
Let measure of arc is the length of corresponding segment.
Image:
And so weird answer: $$ X\approx 12.4428 (\mbox{radius}\approx 7.63599, \mbox{angle}\approx 1.90458) $$ $$ Y\approx 11.0351 (\mbox{radius}\approx 7.63599, \mbox{angle}\approx 1.61503) $$
Solution 2: in the style of "matches":
$X=7$ matches,
$Y=8$ matches:
(if there are $\ge 5$, then we group each $5$ matches into "square").
Of course, there can be also solution in "vectors" style.