Supose that $x_1$ and $x_2$ are solution to the linear system $ AX=B $ , where $B$ is not equal zero then $3x_1-kx_2$ is a solution also if $k = ?$
How to find the value of $A$ ?
Supose that $x_1$ and $x_2$ are solution to the linear system $ AX=B $ , where $B$ is not equal zero then $3x_1-kx_2$ is a solution also if $k = ?$
How to find the value of $A$ ?
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Hints: The fact that $x_1$ and $x_2$ are solutions to $AX = B$ means that $Ax_1 = B$ and $Ax_2 = B$.
In order for $3x_1-kx_2$ to be a solution to $AX=B$, we would need $A(3x_1-kx_2) = B$.
We can use linearity to simplify $A(3x_1-kx_2) = 3Ax_1-kAx_2 = \cdots$.
Can you figure out what value of $k$ makes $A(3x_1-kx_2) = B$?