Having problems with this one using Gaussian Elimination.
Find the solutions for the linear equation system:
$$\begin {cases} x + 5y + 11z = -5\\ 2x + 3y + 8z = 4\\ -x + 2y + 3z = -9 \end {cases}$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 2 & 3 & 8 & 4\\ -1 & 2 & 3 & -9 \end{bmatrix}$$
$$2f_3+f_2$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 6 & 14 & -14\\ -1 & 2 & 3 & -9 \end{bmatrix}$$
$$f_1+f_3$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 6 & 14 & -14\\ 0 & 7 & 14 & -14 \end{bmatrix}$$
$$-f_2 + f_3$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 6 & 14 & -14\\ 0 & 1 & 0 & 0 \end{bmatrix}$$
$$f_2 \ f_3$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 1 & 0 & 0\\ 0 & 6 & 14 & -14 \end{bmatrix}$$
$$-6f_2+f_3$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 1 & 0 & 0\\ 0 & 0 & 14 & -14 \end{bmatrix}$$
$$\frac{1}{14}f_3$$
$$\begin{bmatrix} 1 & 5 & 11 & -5\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & -1 \end{bmatrix}$$
$$-5f_2 + f_1$$
$$\begin{bmatrix} 1 & 0 & 11 & -5\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & -1 \end{bmatrix}$$
$$-11f_3+f_1$$
$$\begin{bmatrix} 1 & 0 & 0 & 6\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & -1 \end{bmatrix}$$
$$6f_3+f_1$$
$$\begin{bmatrix} 1 & 0 & 0 & 0\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & -1 \end{bmatrix}$$
So the solution would be $(0,0,-1)$... which is NOT right. Just looking at the first equation we'd have
$$0 + 5(0) + 11(-1) = -11 \neq -5$$
What did I do wrong? I've been checking my procedure over and over and can't find the problem.
The very first rowop: 2*2+3=7, not six