What does M^(0,1) mean in this equation?

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I typed $$\frac{\partial}{\partial y}(\int f(x)M(x,y)dx)$$ into WolframAlpha and it said $$\frac{\partial}{\partial y}( \int f(x) M(x, y) dx) = \int f(x) M^{0, 1}(x, y) dx$$

What does $M^{0,1}$ mean here? I've never seen that before.